# Simplify (12 – 6i) – (-3 – 8i)?

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Simplify (12 – 6i) – (-3 – 8i)

Simplify (6 + i )(8 – 3i)

2√(x – 8) = 6

√(x + 14 +2) = x

Any help is great, thanks!

• First question:

We change the sign of the second parenthesis so that the minus changes into plus

( 12 – 6i ) + ( 3 + 8i )

Now we remove the parenthesis as they are useless now

12 – 6i + 3 + 8i = 2i + 15

Second question:

we multiply each item in the first parenthesis with two items of the second parenthesis

( 6*8 ) + ( -18i ) + ( 8i ) + ( -3i^2 )

Now we remove parenthesis and do operations

-3i – 10i + 48

Third question:

we divide both by 2

SQRT(x-8) = 3

We raise both sides to the power of 2

x-8 = 9

we add 8 to both sides

x = 17

The last one:

We raise both sides to the power of 2

X + 14 + 2 = X^2

we subtract (X + 14 + 2) from both sides

X^2 – X – 16 = 0

I can’t find any simpler forms.

• 1. Treat as vector addition (12, -6i) + (3, 8i) = (15, -2i) = 15 – 2i

2. (6+i) * (8-3i) = 48 + 8i – 18i – 3iÂ² = 48 + 8i – 18i + 3 = 51 – 10i

3. 2 * SQRT[ x – 8 ] = 6, SQRT[ x – 8 ] = 3, x – 8 = 9, x = 17

4 SQRT[ x + 14 + 2 ] = SQRT[ x + 16 ] = x, xÂ² – x – 16 = 0

By the quadratic formula, x = 1/2 Â± 1/2 * SQRT[ 1 + 64 ] = 1/2 Â± 1/2 * SQRT[ 65 ]

• well the first is

(12-8i)-(-3-8i)=

12+3-8i+8i=15

2nd is (6+i)(8-3i)=

6(8-3i)i(8-3i)=

48-18i+8i-3isquared=

48+3-18i+8i=

51-10i hope that helps!

Don’t know bout the others!

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