CHART:
Compound Formula Ksp
Iron(II) sulfide FeS 3.72×10−19
Magnesium hydroxide Mg(OH)2 2.06×10−13
Lead(II) bromide PbBr2 4.67×10−6
PART B)Use the Ksp values in the table to calculate the molar solubility of Mg(OH)2 in pure water.
C) Use the Ksp values in the table to calculate the molar solubility of PbBr2 in pure water.
THANKS SO MUCH
1 Answer
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General link:
http://chemteam.info/Equilibrium/Equilibrium.html
For FeS, solve it like you would AgCl here:
http://chemteam.info/Equilibrium/Solving-Ksp-probs…
You want to take the square root of 3.72×10−19
For Mg(OH)2, go here:
http://chemteam.info/Equilibrium/Solving-Ksp-probs…
and look at the Sn(OH)2 example.
You’re going to take 2.06×10−13 and divide it by 4, then take the cube root.
PbBr2 is solved in the exact same way as Mg(OH)2
