when a carbon atom has sp3 hybridization, it has…
a. 4 pi bonds
b. 4 sigma bonds
c. 3 pi bonds
d. 1 pi bond and 2 sigma bonds
e. 3 pi bonds and 2 sigma bonds
According to my key sheet the answer is B, but how do i figure it out?
thank u in advance =)
6 Answers
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B is correct. Pi bonds are double bonds, so A, C, D and E are incorrect, as carbon cannot support them…four valence electrons, remember?
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If you were to draw the lewis dot structure for a sp3 hybridized molecule (like CH4), you would see that there are only single bonds (which are sigma bonds).
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sp3 hybridization is a kind of hybridization where one orbital from s-sublevel is hybrid with 3 orbitals from p-sublevel to form 4 hybrid orbitals more capable for binding and forming a strong bond.
Explanation:
Carbon atom in the ground state:
2p | |
2s ||
1s ||
Carbon atom in the excited state:
2p | | |
2s |
1s ||
Carbon atom after sp3 hybridization:
Sp3 | | | |
1s ||
Where the 4 es in hybrid orbitals combine with 4 es from 1s orbital in 4 hydrogen atoms to form methane.
Where 4 sigma bonds are formed.
Sigma bond only formed between hybrid orbitals or a hybrid orbital and a pure one.
I wish that could help.
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its the definition of sp3.
example: CH4 has four sigma bonds b/c there are no double bonds (pi bonds) and it is sp3
sp2 means it has one pi bond, like COH2 (draw the structure, the double bond is C=0)
SP means it has two pi bonds (example CO2— O=C=O)
hope that helpssss!
Source(s): CHEM1331 -
sp3 hybridisation implies involvement of one s & 3 p orbitals.
This results in 4 sigma bonds.
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I mole of anything is defined as 6.02×10^23 units of anything. The mole is a word used instead of the numerical quantity just like the word “dozen” is used instead of the number 12, or the word “gross” is used instead of 144. 1dozen people is 12 people. Since 1 person has 2 arms, 1dozen persons will have 24 arms or 2 dozen arms. 1) 1 mole of CH3COOH contains 4 moles of H 2) 1 mole of CH3COOH contains 2 moles of C 3) 1 mole of CH3COOH contains 2 moles of O
