How much longer does the run take if the coefficient of kinetic friction is 0.17 instead of 0?
I found the time for 0, but don’t know how to change the formula for kinetic friction.
1 Answer
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use F=m*a
for no friction
mgsin(28)=m*a
so
d(t)=.5gsin(28)*t^2
set d=100 and solve for t
for friction
mgsin(28)-mgcos(28)0.17=ma
now d(t)=
.5g(sin(28)-cos(28)0.17)t^2
set d=100 and solve for t
no friction
t= 6.6
friction
t= 8.0
j
