The 10kg block in the figure slides down a frictionless ramp.?

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The 10kg block in the figure slides down a frictionless ramp. (Figure 1)

What is its acceleration?

Here’s a the picture provided:

http://s1272.beta.photobucket.com/user/kurtcopain/…

1 Answer

  • The 10 kg’s weight , 98.1N, has two components.

    The component down the plane is given by Sin 40° = x / 98.1

                                                                                x    = 98.1 Sin 40° = 63.06N

    The 5kg mass is creating an opposing force, up the plane, of 5 x 9.81 = 49.05N

    Therefore, the resultant force down the plane is 63.06 – 49.05 = 14.01N

          Using F = ma  and remembering the 5 kg is being pulled up too,
    
               14.01= 15a

    Acceleration = 14.01 /15 = 0.934 m/s^2

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