Home / Questions / The center of a circle represented by the equation (x + 9)2 + (y − 6)2 = 102 is?

The center of a circle represented by the equation (x + 9)2 + (y − 6)2 = 102 is?

December 1, 2022 0

The center of a circle represented by the equation (x + 9)2 + (y − 6)2 = 10^2 is?

This is the standard form for a circle given its center and radius. You really need to review the basics, because you should be able to see the answer, (-9, 6), easily from that formula.
The center of a circle (x – a)^2 + (y – b)^2 = r^2 is (a,b). Compare to your equation.

The radius is r.
(x+9)² + (y-6)² = 102

center (-9, 6)

radius = √102
(-9, 6)

x: -9, y: 6
C (- 9 , 6 )
(-9, 6)
Exactly in the middle.
(x,y) = (-9,6)