The concrete slab of a basᴇмᴇɴt is 11 m long, 8 m wide, and 0.20 m thick. During the winter, temperatures are.?

NetherCraft 0

nominally 17˚C and 10˚C

at the top and bottom surfaces, respectively. If the concrete has a

thermal conductivity of 1.4 W/m · K, what is the rate of heat loss

through the slab? If the basᴇмᴇɴt is heated by a gas furnace operating

at an efficiency of ηf = 0.90 and natural gas is priced at Cg = $0.01/MJ, what is the daily cost of the heating loss?

2 Answers

  • Q = k × (d)T × Area/thickness

    Q = 1.4W/mK × 7(C) K × 88m²/.2m

    Q = 4.312 kW = 4.312kJ/s

    1 day × 24hr/day × 3,600s/hr = 86,400 s

    86,400s × 4.312 kJ/s = .372557mJ/day

    .372557mJ × 10/9 (efficiency) × $.01/mJ = 4.13952¢ /day

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