The electric field in an aluminum wire is 0.085 V/m. What is the current density in the wire?

2 Answers

• Just divide it by the resistivity of aluminum. 0.085 [V/m] / 2.82×10−8 [Ohm m] = 3.01×10^6 [A/m^2]

• For those of you who still need it 2mm x 2mm wire with 0.085 V/m

  Equation:

  I = EA / R

  Which is from. V = EA ; I = V/R and substituting V.

  Givens:

  A = (2*10^-3) * (2*10^-3) = 4*10^-6 m^2

  E = 8.5*10^-2 V/m

  R_of aluminum = 2.8*10^-8

  Just plug everything in and you’re good to go