The fundamental frequency of a pipe that is open at both ends is 577 .
1)How long is this pipe? Use v = 344 m/s
2)If one end is now closed, find the wavelength of the new fundamental
3)If one end is now closed, find the frequency of the new fundamental
577 Hz *
Open at both ends means antinodes on both ends, length of pipe is 2 times the wavelength of the fundamental.
1) Lambda = 344/577 = 0.5962m
1/2Lambda = Length of pipe, Length of pipe = 0.5962 / 2 = 0.2981m
2) One end closed means close end is a node and open end is an antinode, length of pipe is 4 times the wavelength of the fundamental
1/4Lambda = Length of pipe, Lambda = 0.2981 x 4 = 1.1924m
3) Fq = Speed/Wavelength = 344/1.1924 = 288.5Hz
The fundamental frequency of a pipe that is open at both ends is the frequency of which the wavelength is twice the length of the pipe.
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