The reaction of Cr2O3 with silicon metal at high temperatures will make chromium metal. 2Cr2​O3​(s)+3Si(s) 4Cr(l)+3SiO2​(s)?

NetherCraft 0

The reaction is begun with 140.00 g of Si and 95.00 g of Cr2O3.

How many grams of the excess reactant are left after the reaction is complete?

2 Answers

  • (140.00 g Si) / (28.0855 g Si/mol) = 4.9847786 mol Si

    (95.00 g Cr2O3) / (151.9904 g Cr2O3/mol) = 0.625039 mol Cr2O3

    0.625039 mole of Cr2O3 would react completely with 0.625039 x (3/2) = 0.9375585 mole of Si, but there is more Si present than that, so Si is in excess.

    ((4.9847786 mol Si initially) – (0.9375585 mol Si reacted)) x (28.0855 g Si/mol) = 113.67 g Si left over

  • ok

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