# The table shows the position of a cyclist. Find avg velocity?

0

t (seconds) 0 1…… 2 …… 3…… 4…… 5

s (meters) 0 (1.5) (4.9) (10.4) (17.4) (24.8)

(a) Find the average velocity for each time period.

(i) [1, 3]

???? m/s

(ii) [2, 3]

????? m/s

(iii) [3, 5]

???? m/s

(iv) [3, 4]

???? m/s

(b) Estimate the instantaneous velocity when t = 3.

???? m/s

• Find the average velocity by using the secant slope form… For instance..

1ai) (f(3) – f(1))/2

= (10.4 – 1.5)/2

= 4.45

1aii) (f(3) – f(2))/(3 – 2)

= 10.4 – 4.9

= 5.5

You try the last two parts for 1a) by yourself…

1b) Take points at t = 2 and t = 4 and apply the secant slope form. You should get…

m(3) ≈ (f(4) – f(2))/2

= (17.4 – 4.9)/2

= 12.5/2

= 6.25

Good luck!

• known velocity is purely the slope of a line between 2 factors. delta s / delta t. or (y2 – y1)/(x2 – x1). for 3 seconds, you’re staring at (a hundred and ten – 34) / (5 – 2) , which equals 29.3 infinitely repeating (29 and a million/3). i think of you could calculate the different 2 now which you keep in mind the thought. desire this facilitates.

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