t (seconds) 0 1…… 2 …… 3…… 4…… 5
s (meters) 0 (1.5) (4.9) (10.4) (17.4) (24.8)
(a) Find the average velocity for each time period.
(i) [1, 3]
???? m/s
(ii) [2, 3]
????? m/s
(iii) [3, 5]
???? m/s
(iv) [3, 4]
???? m/s
(b) Estimate the instantaneous velocity when t = 3.
???? m/s
2 Answers

Find the average velocity by using the secant slope form… For instance..
1ai) (f(3) – f(1))/2
= (10.4 – 1.5)/2
= 4.45
1aii) (f(3) – f(2))/(3 – 2)
= 10.4 – 4.9
= 5.5
You try the last two parts for 1a) by yourself…
1b) Take points at t = 2 and t = 4 and apply the secant slope form. You should get…
m(3) ≈ (f(4) – f(2))/2
= (17.4 – 4.9)/2
= 12.5/2
= 6.25
Good luck!

known velocity is purely the slope of a line between 2 factors. delta s / delta t. or (y2 – y1)/(x2 – x1). for 3 seconds, you’re staring at (a hundred and ten – 34) / (5 – 2) , which equals 29.3 infinitely repeating (29 and a million/3). i think of you could calculate the different 2 now which you keep in mind the thought. desire this facilitates.