The normal freezing point of n-octane(c8H18) is -57degrees C.
a)Is the freezing of n-octane an endothermic or exothermic process?
b)In what temperature range is the freezing of n-octane a spontaneous process?
c)In what temperature range is it a nonspontaneous process?
d)Is there any temperature at which liquid n-octane and solid n-octane are in equilibrium? Explain
1 Answer
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a)Is the freezing of n-octane an endothermic or exothermic process? :- freezing releases energy so exothermic
b)In what temperature range is the freezing of n-octane a spontaneous process? :- temperatures below -57 C
c)In what temperature range is it a nonspontaneous process? :- temperatures above -57 C
d)Is there any temperature at which liquid n-octane and solid n-octane are in equilibrium? Explain :- at -57 C, because at the freezing point the two phases are in equilibrium and deltaG = 0
