I need help for this question:
1/a+1/b=1/c Solve for c.
Can you please include this process, too?
8 Answers

abc[1/a+1/b=1/c]
bc+ac=ab
c(b+a)=ab
c=ab/(a+b)

1/a – 1/b = 1/c

1/a + 1/b = 1/c
c(1/a + 1/b) = 1
c/a + c/b = 1
(ca + cb)/ab = 1
ca + cb = ab
c(a + b) = ab
c = ab/(a + b)
Answer: c = ab/(a + b)
Checking equality of sides: substitute c with ab/(a + b):
1/a + 1/b = 1/(ab/[a + b])
1/a + 1/b = (a + b)/ab
ab(1/a + 1/b) = a + b
b + a = a + b

Solve For C

1/a + 1/b = 1/c
(b + a)/ab = 1/c
c = ab/(a + b)

1/a + 1/b = 1/c
Multiply all terms by abc
bc + ac = ab
c(b+a) = ab
c = ab / (a+b)

c=ab/(a+b)

c/a+c/b=1
2c/
Source(s): i am bored