Two particles with positive charges q_1 and q_2 are separated by a distance s?

NetherCraft 0

Along the line connecting the two charges, at what distance from the charge q_1 is the total electric field from the two charges zero?

Express your answer in terms of some or all of the variables s, q_1, q_2 and k = 1 / (4pi*e_o). If your answer is difficult to enter, consider simplifying it, as it can be made relatively simple with some work.

PLEASE HELP and THANK YOU.. ive been trying for sooooooo long and am about to cry 🙁

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2 Answers

  • Let that point be at a distance x from q1

    Then Kq1/x^2= Kq2/ (s-x)^2

    Taking square roots and simplifying, x =s /[1+(q2/q1)^0.5]

  • E. Assuming an identical distance, the rigidity of Q on 2Q is equivalent in value to the rigidity of 2Q on Q. for that reason, had the area R been stored an identical, the two forces could be equivalent. inspite of the shown fact that, via fact the area is being decreased, we could constantly consult with the equation we use to calculate those forces: F = ok(Q1xQ2)/(R^2) because R is squared and is being halved, the final result’s that’s it being divided by potential of a million/4. for that reason, the rigidity would be expanded by potential of four, and be 4F.

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