Use the atomic mass of indium to calculate the relative abundance of indium-113 and indium 115.?

4 Answers

• the average mass of Indium is 114.8183 g/mol

  let X% = In-113

  then (100 -X%) = In-115

  114.8183 = X% of (112.9041 amu) + (100-X)% of (114.9039 amu)

  114.8183 = 112.9041X + 114.9039 – 114.9039X

  1.9998 X = 0.0856

  X = 0.04280

  your answers are

  In-113 = 4.28 %

  In-115 = 95.72%

  p.s. http://ie.lbl.gov/education/parent/In_iso.htm

• Atomic Mass Of Indium

• Indium Atomic Mass

• Using the “Magic Square” I get Ir^113 = 10% and Ir ^115 = 90%