What are the approximate solutions of 2×2 + x = 14 rounded to the nearest hundredth?

NetherCraft 0

x ≈ −2.41 and x ≈ 2.91

x ≈ −2.91 and x ≈ 2.41

x ≈ −5.82 and x ≈ 4.82

No real solutions

4 Answers

  • 2x² + x = 14

    Factor out through completing the square.

    2x²/2 + x/2 = 14/2

    x² + 1/2x = 7

    x² + 1/2x + 1/16 = 7 + 1/16

    (x + 1/4)² = 113/16

    x + 1/4 = ±(√113) / 4

    x ~ −2.91;

    x ~ 2.41

    How I got 1/16 -> ((1/2x)/2)² = (1/4)² = 1/16

  • 2x² + x =14

    x² + ½ x + 1/16 = 7 + 1/16

    (x + ¼)² = 113/16

    x + ¼ = ±(√113) / 4

    x = -.25 ± 2.66

    x ≈ −2.91 and x ≈ 2.41

  • 2x^2+x=14

    =>2x^2+x-14=0

    => x=[-1±√(1^2-4*2*(-14))]/2*2

    x ~ -2.91 & 2.41

  • 2x^2 + x = 14

    2x^2 + x – 14 = 0

    x = (-1 +/- sqrt(1^2 – 4(2)(-14))) / (2*1)

    x = (-1 +/- sqrt(1 + 112)) / (2*1)

    x = (-1 +/- sqrt(113)) / 2

    x = -0.5 +/- sqrt(28.25)

    x =~ 4.82 or -5.82

    The last answer is correct.

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