53P2 how to solve in statistics
2 Answers

we’re finding the number of permutations of size 2 that can be taken from a set of size 53.
This is computed as 53! / (53 – 2)! = 53 × 53 = 2756

The propose of ten numbers is 8 this means that entire fee = 80(8multiplied by ability of 10) now 11th extensive style is now coated in the outcomes the propose will become 9 this means that entire fee = ninety 9(9multiplied by ability of 11) while 80 will become ninety 9 using a million extensive style the linked fee of the 11th extensive style = 19