What is the equivalent capacitance of the three capacitors in the figure?

2 Answers

• V = Q /C

  20μF and 30 μF are in series.

  Combined capacity of these two

  Cs = 20*30 μF / [20 + 30] = 12 μF

  12 μF and 25μF are in parallel

  their combined capacity is

  (12 + 25) μF = 37 μF

  The equivalent capacitance of the three capacitors is 37 μF

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• Ceq= 20*30μF / (20=30) = 12 μFr

  12+13μF = 25 μF