HBr is a strong acid : HBr = H+ + Br-
NH4Br is a strong salt : NH4Br = NH4+ + Br-
the ionic equation is
H+ + Br- + NH3 = NH4+ + Br-
Br- is a spectator ion so the net ionic is
H+ + NH3 = NH4+
NaOH + Ag(NO)3 → AgOH + Na(NO)3 … already balanced … so no balancing required now write it in ionic form like this: Na⁺ (aq) + OH⁻ (aq) + Ag⁺ (aq) + (NO)3⁻ (aq) → AgOH (s) + Na⁺ (aq) + (NO)3⁻ (aq) … [AgOH is insoluble so will be a precipitate] Now to get the net ionic equation write it again BUT leave out common ions that are on both sides of the equation: Ag⁺ (aq) + OH⁻ (aq) → AgOH (s) btw … for this one the middle step really isn’t needed … the final net ionic equation could just be written straight down
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what is the ionic equation for the reaction HBr(aq)+NH3(aq)Yield NH4Br(aq)?