What is the mass of 1.56 x 1021 atoms of magnesium in grams?

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What is the mass of 1.56 x 1021 atoms of magnesium in grams

4 Answers

  • 1.56×10^21 atoms x (1 mole / 6.022×10^23 atoms) x (24.3 g / mole) = 0.0629 g

  • First step, convert the number of atoms into moles (use where 1mole of any atom = 6.022×10^23 atoms):

    1.56×10^21 atoms x (1 mol / 6.022×10^23 atoms ) = 2.59×10^-3 moles

    Final step, convert moles into grams (use the periodic table):

    2.59×10^-3 moles x (24.305g / 1mol) = 0.630 grams Mg

    Good luck!

  • To work out the mass of 1.56 x 10^21 atoms of magnesium is grams is split into 2 parts first we have to convert the number of atoms into the number of moles and we do that using this formula


    n=number of moles

    N=molecules of substance

    NA=avogadro’s number which is 6.02 x 10^23

    n=(1.56 x10^21) / (6.02 x10^23)=0.00259 mol

    then to work out the mass you have to multiply the number of mole(n)

    by the molar mass(M) of magnesium which is 24.3

    m=n x M


    n=number of moles

    M=molar mass

    m=0.00259 x 24.3= 0.0629g of Mg

    mass of magnesium is 0.0629g

    Hope this answers your question=)

  • 1 Mole of Mg is 24.3g.




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