What is the molarity of Cl− in each solution?

NetherCraft 0

1)in 0.180M NaCl

2)0.200M SrCl2.

3)0.150M AlCl3.

please help me… I’ve been trying to do this and i can’t figure out the answer

1 Answer

  • Supposing complete ionization in all cases:

    1)

    (0.180 M NaCl) x (1 mol Cl{-} / 1 mol NaCl) = 0.180 M Cl{-}

    2)

    (0.200 M SrCl2) x (2 mol Cl{-} / 1 mol SrCl2) = 0.400 M Cl{-}

    3)

    (0.150 M AlCl3) x (3 mol Cl{-} / 1 mol AlCl3) = 0.450 M Cl{-}

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