# what is the perimeter of pqr with virtices p(-2,9) q(7,-3) and r(-2,-3) in the coordinate plane?

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• PQR with vertices P(–2, 9), Q(7, –3), and R(–2, –3)

First distance P(–2, 9), Q(7, –3)

The distance (d) between two points is given by the following formula:

d = √{x2 – x1}^2 +{y2 – y1}2

Thus in our case, the required distance is

d = √{7 – (-2) } ^2 + {-3 -9)^2 = 15

So, PQ = 15….one side of PQR

Second distance P(–2, 9), R(–2, –3)

The distance (d) between two points is given by the following formula:

d = √{x2 – x1}^2 + {y2 – y1)^2

Thus in our case, the required distance is

d = √{-2 – (-2) }^2 + {-3 -9)^2 = 12

PR = 12….second side of PQR

Third distance Q(7, –3), R(–2, –3)

The distance (d) between two points is given by the following formula:

d = √{x2 – x1}^2 + {y2 – y1}^2

Thus in our case, the required distance is

d = √{-2 -7}^2 + {-3- (-3) }^2 = 9

QR = 9….third side of PQR

Now you are ready to find the perimeter P = PQ + PR + QR

P = 15 + 12 + 9

P = 36

Hope this helps! (:

• p(-2,9) q(7,-3) and r(-2,-3)

Using the distance formula to find the lengths of each side:

d = SQR[(x2 – x1)^2 + (y2 – y1)^2]

PQ = SQR[(9)^2 + (-12)^2] = SQR(81 + 144) = SQR(225) = 15 (positive root)

RQ = SQR[(-9)^2 + (0)^2] = SQR(81) = 9 (positive root)

RP = SQR[(0)^2 + (-12)^2] = SQR(144) = 12 (positive root)

Perimeter = 15 + 9 + 12 = 36

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