what is the perimeter of pqr with virtices p(-2,9) q(7,-3) and r(-2,-3) in the coordinate plane?

NetherCraft 0

2 Answers

  • PQR with vertices P(–2, 9), Q(7, –3), and R(–2, –3)

    First distance P(–2, 9), Q(7, –3)

    The distance (d) between two points is given by the following formula:

    d = √{x2 – x1}^2 +{y2 – y1}2

    Thus in our case, the required distance is

    d = √{7 – (-2) } ^2 + {-3 -9)^2 = 15

    So, PQ = 15….one side of PQR

    Second distance P(–2, 9), R(–2, –3)

    The distance (d) between two points is given by the following formula:

    d = √{x2 – x1}^2 + {y2 – y1)^2

    Thus in our case, the required distance is

    d = √{-2 – (-2) }^2 + {-3 -9)^2 = 12

    PR = 12….second side of PQR

    Third distance Q(7, –3), R(–2, –3)

    The distance (d) between two points is given by the following formula:

    d = √{x2 – x1}^2 + {y2 – y1}^2

    Thus in our case, the required distance is

    d = √{-2 -7}^2 + {-3- (-3) }^2 = 9

    QR = 9….third side of PQR

    Now you are ready to find the perimeter P = PQ + PR + QR

    P = 15 + 12 + 9

    P = 36

    Hope this helps! (:

  • p(-2,9) q(7,-3) and r(-2,-3)

    Using the distance formula to find the lengths of each side:

    d = SQR[(x2 – x1)^2 + (y2 – y1)^2]

    PQ = SQR[(9)^2 + (-12)^2] = SQR(81 + 144) = SQR(225) = 15 (positive root)

    RQ = SQR[(-9)^2 + (0)^2] = SQR(81) = 9 (positive root)

    RP = SQR[(0)^2 + (-12)^2] = SQR(144) = 12 (positive root)

    Perimeter = 15 + 9 + 12 = 36

    – .–

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