What is the simplest form of the expression below? (BEST ANSWER)?
x^2yz
——–
y^2
X
y
—
2x
(A)
xz
—
2
(B)
2x^3z
———
y^2
(C)
x^2z
——
2y^2x
(D)
z
yes its suppose to be times
7 Answers

multiply the numeratoris by each other and same with the denoms
x^2y^2z / 2y^2x
cancel 1 x and both ys froms up and down
xz / 2
answer A

discover components of each radical For 18, 2 x 9 2 x 3 x 3 so 3?2 is the simplified answer For 32, 2 x sixteen 2 x 2] x [2 x 2 x 8 2 x 2] x [2 x 2 x 2 x 4 2 x [2 x 2] x [2 x 2] x [2 x 2] x [2 x 2] so 4?2 is the simplified answer because of the fact that they have an analogous radicals, you could upload 3?2 + 4?2 = 7?2

A xz/2

is that supposed to be x^2yz/y^2 times y/2x? if yes, the answer is a) xz/2. x on bottom cancels with one of x’s on top (squared means 2 x’s). y squared cancels with two y’s on top. left with x and z on top, 2 on bottom.

A) xz/2

A!

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