1. The water absorbs 42 joules.
2. The water releases 42 joules.
3. The water absorbs 4200 joules.
4. The water releases 4200 joules.
4 Answers
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Q = m*Cp*(del T)
Where m = mass
cp = specific heat capacity = 4.1855 J g–1 K–1 at 15 deg C
del T = temp change = 14.5-15.5 = – 1 deg C
there fore,
Q = 10*4.1855*-1 = – 41.855 J
Hence 42 joules will be release by water when temp is decrease from 15.5 to 14.5 deg C.
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2
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The specific heat capacity of water is approximately 4.2 kilojoules per kilogram per Kelvin. 1 degree Celsius is equivalent to 1 Kelvin.
In your example you have 0.01 kilograms of water and a -1 degree temperature change. So multiply 4.2 kilojoules by 0.01 and -1 to get -42 joules. In other words 42 kilojoules is released (answer 2).
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