1s, 2s, 2p, 3s, or 3p
and explain your reasoning please!
3s + 3p.
Imagine them as “levels”.
Valence here would mean almost “outside”.
so, in this order:
AND, even if we have, let’s say, iodine:
1s; 2s; 2p; 3s; 3p; 4s; 3d; 4p; 5s; 4d; 5p;
Our valence shell is 5 – or “O”.
So, 5s AND 5p contain the valence electrons.
Note that the 4d DOESN’T contain any valence electrons.
Basically just consider the ones with the highest “numbers”.
The atomic No. of chlorine is 17. Hence the electronic configuration is: 1s2, 2s2, 2p6,3s2,3p5. Therefore the valence electron is in the 3p orbital.
Valence electrons are the s and p of the outer most energy level.
For chlorine it would be 3s2, 3p5 total of 7 valence electrons.
So reducing via all the ********, you like us that can assist you pretend lesson plans which you have been in no way assigned and chemistry homework which you in no way did so your instructor might supply you a grade which you in no way earned? what’s your backup plan while your chemistry instructor tries to envision this with the instructor on the different college? Or could we watch for that query for subsequent week? i do no longer think of i could be doing you any favors if I “helped” you, yet i know it is going to take you an prolonged time to realize that. Suck it up and play the enjoying cards you’re dealt.