1s, 2s, 2p, 3s, or 3p
and explain your reasoning please!
6 Answers
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3s + 3p.
Imagine them as “levels”.
Valence here would mean almost “outside”.
so, in this order:
1s;
2s; 2p;
3s; 3p
AND, even if we have, let’s say, iodine:
1s; 2s; 2p; 3s; 3p; 4s; 3d; 4p; 5s; 4d; 5p;
Our valence shell is 5 – or “O”.
So, 5s AND 5p contain the valence electrons.
Note that the 4d DOESN’T contain any valence electrons.
Basically just consider the ones with the highest “numbers”.
Got it?
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The atomic No. of chlorine is 17. Hence the electronic configuration is: 1s2, 2s2, 2p6,3s2,3p5. Therefore the valence electron is in the 3p orbital.
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Valence electrons are the s and p of the outer most energy level.
For chlorine it would be 3s2, 3p5 total of 7 valence electrons.
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