Math with no numbers?!?
these are my choices….
a)log4 5/log4 6
b)log4 6/log4 5
c)log5 4/ log6 4
d)log6 4/log5 4
i think its a…but i don’t know 🙁 please help!
3 Answers

I’ll use log_b as log base b.
Remember, to change bases use this identity: Log_n(a) = log_m(a)/log_m(n).
Log_6(5) = log_4(5)/log_4(6).
You are right, it is a.

a million. one hundred twenty five is 5^3, so log5(base) one hundred twenty five is comparable to log5(base) 5^3, and the log5(base) and the 5 cancel out. what’s left is: log5(base) m = (a million/3)3 = a million 5^a million = m m = 5. 2. once you have constants in front of logs, you could deliver them interior logs as exponents. So: a million/4 log sixteen = log (sixteen^a million/4) = log 2 a million/2 log 40 9 = log (40 9^a million/2) = log 7 This makes your equation: log y = log 2 + log 7 = log (2 7) = log (14) y = 14. 3. once you’re including 2 logs with an analogous base, you could multiply their insides (like the two and 7 in the final subject). in this subject: 2 = log6(base) (2 * (b^2 + 2)) = log6(base) (2b^2 + 4) 2b^2 + 4 = 6^2 = 36 2b^2 = 32 b^2 = sixteen b = 4. 4. upload the 2d term to the two factors of the equation to get: log3(base) (5x+5) = log3(base) (x^2 – a million) because of the fact the two factors of the equation have log3(base) in them, they’d in simple terms cancel. 5x + 5 = x^2 – a million x^2 – 5x – 6 = 0 (x – 6)(x+a million) = 0 x = 6 and x = a million For x = a million, you get log 0, that’s undefined, so x = a million isn’t an answer. the only answer left is x = 6.