# (x – 2)(x – 8) = 0?

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Can someone provide me with a QUESTION using the part of the results (x – 2)(x – 8) = 0? As challenging as possible thank you.

• You’re looking for a question? Sure!

Given the graph denote by:

f(x) = xˆ2 – 10x + 16

Find the following:

(1) x-intercepts

(2) vertex

(3) f ‘(x)

(4) f “(x)

(5) Graph the equation.

(6) BOUNUS POINTS: Find the anti-derivative of the equation.

Best of luck!

I think the integral would be [(xˆ3)/3] + [(5xˆ2)/2] – 16x –> you missed the square! ;o)

• X 2 X 8

• (x-2)(x-8)=0

x=8

(8-2)(8-8)=0

(6)(0)=0

0=0

• (x – 2)(x – 8) = 0

x*x – 2*x – x*8 + 2*8 = 0

x^2 – 2x – 8x + 16 = 0

x^2 – 10x + 16 = 0

• Factor out the equation x^2 -10x +16=0

• Start with x^2 that means you nead x and x to begin with (x )(x ) because x * x = x^2 Then you need to find out which two numbers add up to +2 (theres a +two before the x) and multiply to -8 (the last bit) 2 and 4 look like they will fit (x 2)(x 4) Now what signs do we need to make it all work? +4 and -2 added make +2 and multiplied make -8 so… (x-2)(x+4) Solve by changing the signs before the numbers +2 and -4 🙂

• by zero theorem: either or both (x-2) or/and (x-8) equal(s) to zero

therefore: ( x-2) = 0 or (x-8) = 0

x = 2

x= 8

• You need to use the foil method (first, outter, inner, last. so it would be

x^2 -8x -2x+16 and from that to x^2-10x+16=0

• The product of two numbers is 16, and their sum is 10. Find the two numbers.

Find any maxima or minima of the function

f(x) = (x^3)/3 – 5x^2 + 16x – 7.

• She wants a question.

Find the flux points of (x^3)/3 – 5X + 16 X ? Its the integral of your expression.

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