Can someone provide me with a QUESTION using the part of the results (x – 2)(x – 8) = 0? As challenging as possible thank you.
14 Answers

You’re looking for a question? Sure!
Given the graph denote by:
f(x) = xˆ2 – 10x + 16
Find the following:
(1) xintercepts
(2) vertex
(3) f ‘(x)
(4) f “(x)
(5) Graph the equation.
(6) BOUNUS POINTS: Find the antiderivative of the equation.
Best of luck!
NOTE to Head_Banger_Romeo:
I think the integral would be [(xˆ3)/3] + [(5xˆ2)/2] – 16x –> you missed the square! ;o)

X 2 X 8

(x2)(x8)=0
x=8
(82)(88)=0
(6)(0)=0
0=0

(x – 2)(x – 8) = 0
x*x – 2*x – x*8 + 2*8 = 0
x^2 – 2x – 8x + 16 = 0
x^2 – 10x + 16 = 0

Factor out the equation x^2 10x +16=0

Start with x^2 that means you nead x and x to begin with (x )(x ) because x * x = x^2 Then you need to find out which two numbers add up to +2 (theres a +two before the x) and multiply to 8 (the last bit) 2 and 4 look like they will fit (x 2)(x 4) Now what signs do we need to make it all work? +4 and 2 added make +2 and multiplied make 8 so… (x2)(x+4) Solve by changing the signs before the numbers +2 and 4 🙂

by zero theorem: either or both (x2) or/and (x8) equal(s) to zero
therefore: ( x2) = 0 or (x8) = 0
x = 2
x= 8

You need to use the foil method (first, outter, inner, last. so it would be
x^2 8x 2x+16 and from that to x^210x+16=0

The product of two numbers is 16, and their sum is 10. Find the two numbers.
Find any maxima or minima of the function
f(x) = (x^3)/3 – 5x^2 + 16x – 7.

She wants a question.
Find the flux points of (x^3)/3 – 5X + 16 X ? Its the integral of your expression.